Physics problem... Stumped (1 Viewer)

SWJJ

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A satellites are placed in a circular orbit that is 2.90 × 10 ^6 m above the surface of the earth. What is the magnitude of the acceleration due to gravity at this distance?


not sure how to set this up...
 

ra

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If it's in orbit, it shouldn't be accelerating... it should be at constant velocity.
So 0.

(Discounting the eventual drop to Earth, which I guess would mean that it is slowly.... very slowly... accelerating toward Earth)
 

Jonesy77

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In my day, we had to cheat off of other classmates. Man, the world has changed
 
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SWJJ

SWJJ

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If it's in orbit, it shouldn't be accelerating... it should be at constant velocity.
So 0.

(Discounting the eventual drop to Earth, which I guess would mean that it is slowly.... very slowly... accelerating toward Earth)


acceleration is not just a change in velocity, but a change in direction as well.

The force that pulls the sat down towards the earth, instead of it flying straight into space, is the acceleration.

I dont want the answer jonesy, just how to set it up, I dont have the mass of the sat so I cant calculate it that way... not sure where to go..
 

taygolf

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^^^ he does not know the mass only the distance.

For some reason this strikes me as a quick question if the satellite is just orbiting the earth with no acceleration other than the pull of gravity wouldn't the answer simple be 9.82m/s^2.

Or is it different since it is in space and not here on earth?

Just a thought to look at

T
 
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SWJJ

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http://www.daviddarling.info/encyclopedia/A/accgrav.html

The acceleration that an object experiences because of gravity when it falls freely close to the surface of a massive body, such as a planet. Also known as the acceleration of free fall, its value can be calculated from the formula


g = GM / (R + h) 2


M should be the mass of the earth plus the mass of the sat, I will assume the mass of the sat is inconcesquential compared to the mass of the earth and work the proble set up like that..
 

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