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I came up with the same thing. Go with it.
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If all you need to find is the force of gravity on the object, it's
Fg=G(m1m2/r^2)
Remember to add the radius of the Earth to 2.90 × 10 ^6 m to get the value for r.
Fg=G(m1m2/r^2)
That looks correct from what I remember, but what does the big G stand for.
That looks correct from what I remember, but what does the big G stand for.
I figured it was a constant.
actually i think as the orbit decays it begins to fall to the earth shortening its orbit length and causing it to increase in speed....
just a thought. no facts to back it up...